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Projectile Motion Calculator

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### Physics of 2D Kinematics & Parabolic Trajectories Projectile motion analyzes objects propelled into space subject only to the downward force of gravity (neglecting aerodynamic drag). ####.

Reviewed by Ahmad Faraz · BSCS
Last updated:
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⚙ Input Values

📊 Results

Primary Trajectory Summary
Max Range: 63.73 m (209.10 ft) | Max Height: 15.93 m | Flight Time: 3.61 s
Total Horizontal Range (Distance)
63.73 m (209.10 ft)
Maximum Altitude / Peak Height (H_max)
15.93 m (52.27 ft)
Total Flight Time (Hang Time)
3.605 seconds
Time to Trajectory Apex
1.803 seconds
Initial Velocity Components (Vx, Vy)
Vx = 17.68 m/s, Vy = 17.68 m/s
Impact Landing Speed & Angle
25.00 m/s (55.9 mph) @ -45.0°
✦ Parabolic Kinematics Analysis
Trajectory Kinematics: Launching at 25.00 m/s (55.9 mph) at 45° from 0.00m elevation achieves a maximum range of 63.73 m (209.10 ft) and peak altitude of 15.93 m (52.27 ft) with 3.61s hang time. Apex is reached in 1.80s. Ground impact speed is 25.00 m/s (55.9 mph) at -45.0° to the horizon.
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📐 Formula

Classical 2D kinematics equations of parabolic projectile motion under constant acceleration (\(g\)): Components: v_0x = v_0 ( ), v_0y = v_0 ( ) to Trajectory Peak: t_apex = v_0yg = (v_0 ( ) ÷ g) Altitude: H_ = h_0 + v_0y^22g = h_0 + (v_0^2 ^2( ) ÷ 2g) Flight Time: t_flight = v_0y + √(v_0y)^2 + 2 g h_0g Range: R = v_0x × t_flight = (v_0 ) × t_flight (For \(h_0 = 0\): \(R = (v_0^2 (2 ) ÷ g)\))

💡 Practical Example

✅

For example, launching a projectile at 25 m/s (55.9 mph) at an angle of 45° from ground level): \. Peak height is \}}\). Total flight time is \(\mathbf{3.605\text{ seconds}}\), and horizontal range is \}{9.80665} = \mathbf{63.73\text{ meters (209.09 ft)}}\).

📖 About Projectile Motion Calculator

Physics of 2D Kinematics & Parabolic Trajectories

Projectile motion analyzes objects propelled into space subject only to the downward force of gravity (neglecting aerodynamic drag).

Independence of Perpendicular Motions

Galileo Galilei demonstrated that horizontal motion and vertical motion are completely independent:

  • Horizontal Motion (X-axis): Moves at constant velocity), so x(t) = v_0x t.
  • Vertical Motion (Y-axis): Undergoes constant gravitational acceleration), so y(t) = h_0 + v_0y t - (1) / (2) g t^

2.

Optimum Launch Angles

  • Flat Ground): Maximum horizontal range occurs at exactly 45°.
  • Elevated Cliff Launch (h_0 > 0): Maximum range occurs at an angle less than 45° (typically 35° to 42° depending on cliff height).

How to Use This Calculator

Enter your Initial Launch Velocity (v₀) (e.g. 25), Velocity Unit — choose from Meters per Second (m/s), Feet per Second (ft/s), Kilometers per Hour (km/h), Launch Angle (θ in degrees, 0° to 90°) (e.g. 45), Initial Launch Height (h₀ above ground) (e.g. 0 for flat ground), Height Unit — choose from Meters (m), Feet (ft), and Gravitational Acceleration (g) — choose from Earth (9.80665 m/s² / 32.174 ft/s²), Moon (1.62 m/s²), Mars (3.72 m/s²). Measure twice before entering dimensions — small measurement errors scale up significantly in material estimates.

The Formula

Classical 2D kinematics equations of parabolic projectile motion under constant acceleration (g): Components: v_0x = v_0 (θ), v_0y = v_0 (θ) to Trajectory Peak: t_apex = v_0yg = (v_0 (θ)) / (g) Altitude: H_ = h_0 + v_0y^22g = h_0 + (v_0^2 ^2(θ)) / (2g) Flight Time: t_flight = v_0y + √(v_0y)^2 + 2 g h_0g Range: R = v_0x × t_flight = (v_0 θ) × t_flight (For h_0 = 0: R = (v_0^2 (2θ)) / (g))

Worked Example

For example, launching a projectile at 25 m/s (55.9 mph) at an angle of 45° from ground level): . Peak height is . Total flight time is 3.605 seconds, and horizontal range is \9.80665 = 63.73 meters (209.09 ft).

Understanding Your Result

Add a 10% waste factor for square-cut tile or carpet, 15% for diagonal tile installation, and 10–15% for hardwood with natural variations. Flooring is sold in boxes covering fixed square footage — always round up to full boxes. For tile: grout joint width affects coverage; wider joints reduce tile count. For carpet: roll width (typically 12 ft) determines seam placement — minimize seams in high-visibility areas.

💡 Methodological Standards & Calculation Accuracy

  • All calculations are performed client-side in your browser using verified, standards-compliant mathematical algorithms.
  • Results are provided for educational and informational analysis; verify critical applications with certified domain specialists.
  • Ensure input values are entered in consistent units matching the selector options to guarantee accurate outputs.
  • Periodic recalibration is recommended whenever baseline assumptions, operating parameters, or external conditions change.

Results are for informational and educational purposes only. Always verify critical decisions with a qualified professional.

❓ Frequently Asked Questions

What angle gives the maximum range in projectile motion?

On flat ground without air resistance, a 45-degree launch angle produces the maximum horizontal distance. When launching from an elevated platform, the optimal angle is slightly less than 45 degrees.

How do you calculate maximum height in projectile motion?

Maximum height is calculated as H_max = h0 +)² / (2g), where h0 is initial height, v0 is launch velocity, θ is launch angle, and g is gravitational acceleration.

Does projectile mass affect flight time or range?

In ideal physics neglecting air resistance, mass has no effect on trajectory, flight time, maximum height, or range because gravitational acceleration is constant for all masses.

How do you calculate horizontal range?

Horizontal range equals the horizontal velocity multiplied by total flight time: R =) × t_flight. On level ground, R =) / g.

What is the projectile's velocity at the peak of its trajectory?

At the peak apex, the vertical velocity is zero, so the projectile's speed equals purely its horizontal velocity: V_peak = Vx = v0 × cos(θ).

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